LOGARITMA

      
1.  Jika ⁴log ⁴log x – ⁴log ⁴log ⁴log 16 = 2, maka …

A. ²log x = 8

B. ²log x = 4

C. ⁴log x = 8

D. ⁴log x = 16

E. ¹⁶log x = 8

PEMBAHASAN :

=  ⁴log ⁴log x – ⁴log ⁴log ⁴log 16 = 2

=  ⁴log ⁴log x – ⁴log ⁴log ⁴log 4² = 2

= ⁴log ⁴log x – ⁴log ⁴log 2(⁴log 4) = 2

= ⁴log ⁴log x – ⁴log ⁴log 2 = 2

= ⁴log ⁴log x – ⁴log ^{2^2}log 2 = 2    

= ⁴log ⁴log x – ⁴log ½(²log 2) = 2

= ⁴log ⁴log x – ⁴log ½ = 2

= ⁴log ⁴log x – ^{2^2}log 2^-1 = 2

= ⁴log ⁴log x – (-1/2) ²log 2 = 2

= ⁴log ⁴log x + 1/2 = 2

= ⁴log ⁴log x = 2 – ½

= ⁴log x = 4^3/2 = 8